Philip and DMackson (dad) who came up with 1089 feet and to Chris Rowan's students, Roxanna Muniz and Susan Rico, who came up with 1080 feet. We also want to recognize Mr. Grott, Mrs. Phaneuf, and Mrs. Grady's classes for having the motivation to dig in and do some very rigorous brain teasing thinking! Nice effort! Token prices will be on their way to Philip and Mr. Rowan's students very soon! ******************************************************************* These are the responses sent in for the first week's MTO Challenge Question: ********************************************************************* DMackson@aol.com To: jwee@mail.arc.nasa.gov Subject: CHALLENGE QUESTION My son Philip who is 8 and in third grade (we home school) has been reading a lot about space recently. His first answer to your question was 820 feet. When pressed for the reason he said it was because Mars is half the size of earth. In talking about it further it seems that he read also that his weight on Mars is about 1/2 that of earth. He got his books and we looked up together that if you were 85 lbs. on earth you would be 35 lbs. on Mars. So using fractions our collective answer is 1089 feet. Or, we could make the ball heavier. *********************************************************************** From: crowan@ies.net (Rowan, Chris) Subject: Our answer to the challenge question Roxanna Muniz and Susan Rico (two of my students) took 410 and divided it by 0.38, which is Mars's fraction of Earth's gravity. In other words, Mars's gravity is 38% of Earth's gravity. We reasoned that if we could knock a baseball 100 feet on Earth and went to a planet with exactly half Earth's gravity, we would be able to knock the ball twice as far, or 200 feet. So, if Mars's gravity was exactly half earth's gravity, we should be able to knock the baseball twice 410, or 820 feet. Since Mar's gravity is less than half Earth's gravity (38 percent), then the answer we get SHOULD be greater than 820. So, we first tried multiplying 410 by .38, but got 155.8, which is much smaller than 820. Then we tried dividing 410 by .38 and got 1079.9474, or 1,080 feet. This is more than 820, so we figure this is the correct answer. ANSWER: The center field fence should be placed 1,080 feet from home plate. Regards, Chris Rowan *********************************************************************** Dave GrottYANKEE STADIUM ON MARS First we looked in the World Book Encyclopedia and found out that an object that weighs 100 pounds on earth would weigh 38 pounds on Mars(The gravity of mars is three-eighths that of the Earth). We then multiplied 410 feet(the distance from home plate to the center field fence of Yankee Stadium) times 38 and got 15,580 feet for what the distance from home plate to the center field fence on Mars. Patrick Cavuto Damien Faillace Tim Hicks Chris Johnson Mark Leitem Josh Purnell Brian Pecchia Austin Rapp Mr.Grott's Sixth Grade Alden Place Elementary School Millbrook, New York ******************************************************************* Dave Grott Mrs.Phaneuf's Class We think that the length should be 15580 feet because the gravity on Mars is 38% of that on earth. Mrs.Phaneuf's 4th Grade Alden Place Elementary School Millbrook, New York ********************************************************************* Challenge Question - Mrs. Grady Tim Porell and Jillian Sakovits Distance is one foot. We think that there is almost no gravity on Mars so the ball would not go very far. Mrs.Grady's Third Grade Class Alden Place Elementary School Millbrook, New York ********************************************************************** Dave Grott Subject: Challenge Question - Mr.Grott - Girls We all think that the answer to the baseball problem is 1230. We got that answer by finding out that Mars's gravity is three eighths less than Earth's gravity. We changed three eighths into three ninths which equals one third because one third is easier to work with. We then figured out that 410 was one third of the distance that the center field fence would be on Mars. We multiplied four hundred ten by three and got 1230. We would like to know if the bat and ball would have to be lighter or heaver on Mars. Submitted by: Sarah Schappach Laura Donovan Kelly Brennan Sarah Kading Heather Tyler Stacey Schmouth Danielle Ryan Karissa Thompson Christine Van Kessel Kim Macy Rebecca Raymond The Young Ladies of Mr. Grott's 6th Grade Alden Place Elementary School PO Box AA, Alden Place Millbrook, New York 12545 ******************************************************************** We decided that distance on Mars = distance on earth/gravitational pull We use the www to find the relationship of Mars=.377 of Earth's gravity so distance on Mars= 410/.377 which comes to 1087.33 ft. rounded off to 1088 so the center field fence would be set back at 1088 ft from home plate. Also you could use the same ball field if you change the mass of the baseball being hit (large ball) Mrs. Wall's fourth grade students John Wayland Elementary Bridgewater, VA ******************************************************************** Our sixth grade class talked about the challenge question in class with Roberts and this is what we came up with. We looked up the gravity of Mars and found it is .38 of Earths gravity. Another way to say it, we think, is that Earths gravity is 2.6 times stronger than Mars. So, we multiplied the center field fence distance on Earth by 2.6 and we got 1066 feet. We think there are other things the Martian Baseball Commissoner needs to think about. Would you change the weight of the ball and bat in the same proportions? Would the pitcher be 2.6 times further away? What would happen to drop rate of the ball? Would the batter swing faster which might make the ball go even further? Would the speed be 2.6 times faster of the pitch? Actually, we have more questions than answers! But, this was fun to do Bharath & Andrew for Room 305 Zellerbach Elementary Camas, Washington Mrs. Jo Lynne Roberts Sixth Grade Teacher...of a stellar class! ******************************************************************** Hi, I am a student from St. Anne School, and I think I figured out the challenge question. The fence would need to be about 1086.7 feet back in Mars, so it would be just as hard to hit a home run. I figured this out by making a ratio 9.78(earth) : 3.69(mars). This equals out to 2.65 times 410, equaling out to 1086.7. Well thank you for your time! Sincerely, Sandy ******************************************************************** From: DMLedet@aol.com The answer to challenge #1 is 154,570 feet back. ******************************************************************** From: wecooks@ix.netcom.com (Janet K. and James R. Cook) Hope it's not too late to enter the challenge question. I asked my kids last night and on emade a guess. Others may turn somethin gin tonight. Evan's guess was 566 ft. Thanks jkc ******************************************************************** We think that the distance from Home Plate to the Centerfield fence should be 3500 feet. the gravity on Mars is 9 times less than on earth. Mr.Makar's Third Grade Class Alden Place Elementary School Millbrook, New York ********************************************************************